-16t^2-21t+106=0

Solution for -16t^2-21t+106=0 equation:

-16t^2-21t+106=0

a = -16; b = -21; c = +106;
Δ = b2-4ac
Δ = -212-4·(-16)·106
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-85}{2*-16}=\frac{-64}{-32}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+85}{2*-16}=\frac{106}{-32}
=-3+5/16
$